თვიურა დაუძახე,ხომ იცი რატომაც (?!)

The red and purple line show you the upper and lower limits of the range. I'm going bang in the middle since the low effects described aren't sufficient and the high effects are too much to the knowledge we have. The blue line is our amplitude and that is 50mm. Which isn't too bad.

Now we need an estimate for the distance that the island is from the epicenter. What we must note for this method is that there are no islands around Marineford about from Sabaody. More precisely, there is nothing in the triangle that links the three locations, Marine HQ, Impel Down and Enies Lobby.

6 days remained to Ace's execution

http://www.mangapanda.com/103-2631-1...apter-524.html

They arrived in Impel Down in 4.5 days.

http://www.mangapanda.com/103-2632-1...apter-525.html

The marine battleships are more advanced than any battleship we have in the real world, being able to fire cannons powerful enough to take down skyscrapers and displace millions of tons of water as such I will liken them to the fastest known battleship.

http://www.top10fastest.com/fastest-...fastest-ships/

Which is 32 knots or 16.46m/s.

This is a rescaling. It turns out that 80.6px is more or less the majority of the time it took for the ship to reach the Gaol. How do we know this?

When the escape crew broke out of Impel Down and passed through the gates of justice to enter the Tarai Current towards Marineford it was stated that there was 4 hours until Ace's execution.

http://www.onemanga.me/one-piece/548/18/

They arrived.

http://www.onemanga.me/one-piece/550/9/

The execution hadn't taken place yet. So that blue line you see drawn across the Tarai Current was crossed in less than FOUR HOURS yet it makes up more or less half the total distance. So the Tarai Current heavily speeds up the journey.

16.46*(4.5-0.16)*24*60*60 = 6172105m or 6172.105km. This is a realistic distance based on distances we already know to be true in the One Piece verse.

80.6px = 6172.105km
173 + 272.5 + 207 = 652.5/3 = 217.5px

We worked out an average above as we don't know the direction the island is in.

217.5px = 16655.49km (at least)

I don't know how to find an accurate one as of this moment, so I'll assume 4000km since that was the minimum distance between Dressrosa and Punk Hazard. And because the water around Sandy Island was as wide as Sandy Island itself and as we know Sandy Island was >3000km.

http://crack.seismo.unr.edu/ftp/pub/...magnitude.html

The above formula will calculate the magnitude according the Richter scale.

We need to get a value for t.

http://www.geo.umass.edu/courses/geo105/Lecture-12.pdf

16655.49km is our distance. We need it in miles. After converting it to miles we divide that value by 5.7.

16655.49km gives us a time difference (delta[t]) of 1816s.

M = log(base10)50+3log(base10)[8*1816]-2.92 = 11.27 or 1.2 teratons

More evidence of Whitebeard's quakes being at a magnitude of >9 is below:

http://wiki.answers.com/Q/How_strong...ause_a_tsunami

If you recall Blackbeard sent tsunamis of a large height to Sabaody.

Whitebeard Cannot Be Escaped (Can Prime Whitebeard Destroy The World?!?)

http://www.mangastream.to/one-piece-...53-page-7.html

Tsuru basically confirms that Whitebeard's abilities can reach anywhere in the planet (other interpretations of the claim include Tsuru possibly talking about the battle itself and not Whitebeard's powers, either way it's something to think about). Prime Whitebeard should definitely be capable of this. For this of course we need the size of the planet:

http://www.narutoforums.com/blog.php?b=20265

Use the radius to calculate the circumference.

Cir = 942478km

90 : 900
94247.8 : 942478

Half it.

47123.9

delta[t] = 47123.9s

We'll go for the low end on the nomograph for this one as the tremors may not be severe.

M = log(base10)20+3log(base10)[8*47123.9]-2.92 = 15.11 or 697 petatons

Hmm, maybe Primebeard can destroy the world.სურათებიც იყო დართვა მეზარება ;დ

The feat:

http://mangafox.me/manga/one_piece/v42/c407/18.html
http://mangafox.me/manga/one_piece/v42/c408/2.html

We'll let McDave get the full credit for this one, I'll just change a few values.

Quote:
Chain of Events:
1.)The Feat is straightforward Nami spawns a Cloud
2.) Nami shoots a Ball Lightning into it
3.) Kalifas Notices the Cloud ( Nami did strange stuff like Water doubles before)
4.) Lightning Rains down on Kalifa and we see a Speach Bubble for her with a Question Mark hence she was surprised by the Lightning not by the attack.
McDave took a "reaction time" approach, I'm going to get the speed of her DF activation instead as the main point of the calculation.

http://mangafox.me/manga/one_piece/v42/c408/3.html

The above scan gives me what I need. It shows that Kalifa's bar of soap activates by "rising", so the velocity is in a single direction at 90 degrees. So we only need Kalifa's height for our distance which Dave has already acquired.

The relevant distances:

Spoiler:

Quote:
Scaling Kalifa:
Nami 53px=1.69m
Kalifa 61px->1.945m

Scaling Cloud Height:
We use almost ceiling Height lowend because the Cloud is very distorted in most Panels.

Nami aimed right above Kalifa the Horizontal Distance is hence near zero.

Vertical Distance is 322px or 5.44m
We subtract Kalifas height as her Head wasnt burned-
5.44m-1.945m=3.494m
Enough said. We're using 150,000m/s to work out her reaction time.

3.494/150000 = 0.00002329333

1.945/0.00002329333 = 83500m/s or Mach 245

So it turns out that the CP9 actually ARE massively hypersonic like our ancestors predicted. All of that Soru scaling actually made sense.

Because of arguments made that the bar of soap is formed in other ways, I'm going to opt to go with a reaction time alternative, that way no-one can complain about the way it's formed as it's not relevant.

1/0.00002329333 = 42930m/s or Mach 126

I striked out everything that's not relevant. The situation with this now is simple. Kalifa can follow lightning from close range no issues. However, someone more capable in Blueno could not follow G2 Luffy's Jet Pistol.

This is simple logic. A must be greater than B. This is no different to a character dodging a bullet, then the character who dodged said bullet being blitzed, the "blitzer" must logically be faster than the bullet. There's no silly speed blitz tropes involved here. Blueno straight out commented that he could not follow G2 Luffy's attacks or movement. Go to the chapter "Gear 2nd" to find the evidence.

Mach 441+ is the final number for pre-skip G2 Luffy.

I'd like to thank my momma, YOUR momma, and McDave.

The numbers chose me, I simply listened to them.

I am aware the of the shitstorm that will be started as a result of this realization.

Mach 441 is the final number. The meteor calculation is full of low ends. Maybe Rob Lucci actually is Mach 500.

102px = 348.38m
136px = 464.51m
151px = 515.74m

The volume of the sphere can be calculated using this:

http://www.basic-mathematics.com/vol...alculator.html

V = 52478791.59177833m^3

Going to assume the rock is granite, since granite is a common igneous rock and it was near a volcano.

GPE = mgh

GPE = (52478791.59177833*2600)*(9.8)*(515.74) = >>164.8 kilotons (since it fell from further up and he also stopped the avalanche of sand and earth, if I calculated everything this shit would probably be nearing 500 or so kilotons)

Usopp stopped it dead in its tracks so he'd need the same amount of energy in the opposite direction as far as the tension of his move is concerned.

Let's begin by working out the amount of tree bark that was "fragmented" (there's actually none of it that remains afterwards so it was probably vaporized but we won't go there).

Diameter: 161.84m
Height: 324.38m

V = pi*r^2h
V = pi*(161.84/2)^2*(324.38) = 6,672,916.5m^3

Now, it's clear the wood wasn't fragmented so we won't deal with that. We will instead go down the thermal energy route (since in conjunction with Kizaru's blast having some concussive force all it really is, is a steel melting fireball).

Density of Wood (Oak): 600kg/m^3 [minimum]
Specific Heat Capacity of Wood: 1700
Temperature Wood Chars At: 280 Degrees Celsius

m = 6672916.5*600 = 4003749900kg
C = 1700
deltaT = Assuming the wood started off at 30 degrees (since it's pretty sunny in Sabaody), that would make the temperature change 250 degrees

Q = mCdeltaT = (4003749900)*(1700)*(250) = 1701593707500000J or 406.7 kilotons of thermal energy.

p = m/V

m = p*V = 999.1026*12864022972.933427 = 12835381225784.1907247845kg

Q = (12835381225784.1907247845)*((4.1813)*1000)*14 = 751360113271200113.4855800179J or 179.579376977 Megatons

Naturally the latent energy too.

Q = (334*1000)*(12835381225784.1907247845) = 4287017329411919702.078023J or 1024.621732651 Megatons

179.579376977 + 1024.621732651 = 1204.201109628 Megatons or 1.2 Gigatons or 24x the energy of the Tsar Bomba

Darth calc'd the size of Fujitora's crater on the beach to be 842.87m in width, and it spans pretty much the entirety of the beach.

I think that's the biggest stretch of shore.

(842.87/3.6)35.36=8278.86m

(842.87/3.6)27.8=6508.83m

Aellipse=pi*a*b
A=pi*4139.43*3254.415
A=42321723.8m^2

Dartg-sama insists on 3px, so...

(50/3)193.61=[b]3226.8km

(3226.8/5.385)93=55727.5km

Now we have to find the size of OP's planet.

320/16.5=19.4

This means that any island shown to us must have an expanse of water 19.4 times its own size surrounding it to be considered Alabasta.

The indicated area is the closest to these parameters that we can possibly get that is apparent to me.

Under the greed dot is an island. In the interest of a middle-ground, 1px is used for Alabasta's size rather than 8.544px for the area of water around the island.

The diameter of the globe is 93px.

3226.8*93=300,092.4km.

Brook = 8 pixels (yes, the red line is Brook, you can confirm that much in the top panel)

Pillar Diameter = 36 pixels

Pillar Diameter/Brook = 4.5

Brook = 2.86 meters (technically 2.66 meters, but Oda claimed his hat adds 0.2 more meters)

Pillar Diameter = 12.87 meters

Spoiler:

Pillar Diameter = 21 pixels (Well, this pillar is closer to the mangrove than the one I measured in the previous scan, and they're all basically the same size, so meh)

Mangrove Diameter = 507 pixels

Mangrove Diameter/Pillar Diameter = 24.143

Mangrove Diameter = 310.72 meters

Here? I'm going to get the total size of the mangrove and get the height of the tree kizaru left after his kick (which, if you look here, you'll notice he left roughly up to about the number length below the number)

And remember fuckers, the mangroves around here are all of similar height and dimension (barring where the hell the roots are sprouting out of them anyway)

Mangrove Diameter = 47 pixels

Total Mangrove Height = 674 pixels

Height Left By Kizaru's Kick = 536 pixels

Total Mangrove Height/Mangrove Diameter = 14.34

Height Left By Kizaru's Kick/Mangrove Diameter = 11.404

Total Mangrove Height = 4,455.725 meters

Height Left By Kizaru's Kick = 3,543.451 meters

Spoiler:

Mangrove Diameter = 118 pixels

Stump Height = 140 pixels

Stump Height/Mangrove Diameter = 1.186

Stump Height = 368.514 meters

With both that and the previous figure I got above, I can figure out how much of the tree Kizaru's kick took out.

Total Height Of Tree Remaining After Kick = 3,911.965 meters

Now subtract that from total tree height.

Height of Tree Destroyed = 543.76 meters

Awesome.

Volume = PIr^2*H

Destroyed Tree Volume = 41,232,109.52 m^3

Q = MCdelta(T)

Tree Density = 600 kg/m^3

Destroyed Tree Mass = 24,739,265,710 kilograms

Temperature Change = 250 C

Specific Heat = 1,700

Kick Energy = 10,514,187,930,000,000 joules or 2.513 megatons